Yes, but the power level is 10%. And then there is also "Skin of Evil" and "Rise."Mr. Oragahn wrote:The only ones which can be measured by DET, was Masks. First, your figure was about a total energy deposited into the commet. Divided over the duration of the process, the wattage became lower.
While it isn't absolutely required in the sense you describe, the visuals confirm as best as possible the "real time" nature of the pacing. I.e., require as strongly as possible given the lack of a complete continuous single cut.There's just as much evidence to point out that the phaser, at this rate, would have needed more than one hour to melt the whole comet. Of course, for the whole discussion, I have pointed out how this episode is hardly consistent. I don't expect Picard and co sit in the birdge for more than one hour, and resume "panic and tension" a few seconds before the final ice goes off... in the most unscientific and absurd way. Yes, even the way ice melts is stupid. Not mentioning the fact that the alien station was supposed to be in the core of the comet - as pointed out by dialogue mentionning the source of the signal - not in the outskirt of the comet, as the visuals show it.
... in vacuum, you have either vapor or ice for most substances. Liquid is not stable.There's also the fact that Geordi planned to melt the ice, not vapourize it.
You wouldn't notice this on this scale with this much structural irregularity.Besides, I'm curious as to how the ice didn't break. No matter how low the yield would be, just to raise temp strictly at the first fraction of the first degree necessary for fusion, or say... sublimation, even pouring cold water on ice will crack ice. And I'm not talking about temps necessary for vapourisation mind you.
By which you mean one on-screen Okudagram (in addition to the notoriously unreliable TM, but the two are fortunately similar in this case) ... by which, in reply, I have this to say:All cross sections and caps of torpedos I've seen show that there's enough room for only two warheads. All the rest is taken up by whatever's necessary to protect and fly that torp.
The shot above, I think used for the tech manual, is the same than the shot of the mark XXV displayed on one of the Voyager computer screens.
It's a very simple fact.I, earlier wrote:especially considering that we know, from "The Emissary," that functional drive and shield systems of a photon torpedo can be contained within the outer shell exclusively, suggesting that the entire interior is potentially modular.
Perhaps the standard load of a torpedo is only two (or four, actually; the Voyager cutaway again leaves room for possible warheads of the same size immediately below) - but you clearly have the option to stick two dozen standard warhead modules in there.
(There's also another probable bit I'm neglecting, and that's antimatter used for drive fuel.)
And there are plenty of ways in which a gravimetric warhead could have a standard yield higher than its own mass in annihilated matter - namely, by imploding half the torpedo into a pocket singularity.More about the yields...
This, besides, does not negate the very fact that the gravimetric warhead is incredibly light. We can see that the trek guy is holding a warhead with the tip of his fingers, not even bracing the device against his right thumb, and not even putting a hand underneath it, to gain a better grip.
Above all, he's holding it with arms stretched in front of him.
A 2-3 kg warhead is the utmost acceptable maximum weight estimation for that device. I have all the training bench & muscle stuff at home to make quick empirical tests.
There is just no way the guy could hold a device that way, if it was more than 2-3 kg.
FYI, most of that "neutrino waste" is mainly a third-order product down the decay chain.Of course, to obtain such a yield, the torpedo would be nothing more than an inert casing, which would need to be propelled by the launch tubes, and never gain any extra acceleration. No shields. No sensors. No guidance systems. Nothing but a shell, filled with warheads.
And in fact, if a warhead contained 1 kg of anti deuterium, its real yield would be of 21.48 megatons (due to more than a half of the energy going off via neutrino waste), assuming a near perfect reaction. So to get a 1 gigaton yield of destructive force, you'd need 46.5 warheads crammed into that torpedo.
I think it will be hard to fit that many inside your typical black UFP shell.
Take the classic proton-antiproton reaction. It gives off about 30% of its energy in hard gammas, and then about 70% in pions of either positive or negative charge. The pions - after having traveled some 20 meters at their speed - in turn decay to muons and muon neutrinos, or the anti- counterparts. Muon neutrinos are only in the hundred keV range, negligible; muons, as it so happen, can interact with matter fairly well with matter for the microseconds they exist, and decay into a combination of electrons and neutrinos (or positrons and antineutrinos).
In short, if there is significant containment of the annihilation reaction and interference through other objects (e.g., the rest of the torpedo, a material target, et cetera), we can expect to lose not nearly so much energy to, as you put it, "neutrino waste."
And that's not mentioning the possibility of a "high yield" module that - unlike a spherical module - actually fills the available space, more than doubling the amount of available antimatter.
Watch "Emissary," remembering that the torpedo must include everything necessary to send a diplomat for a significant warp hop. Inertial compensation, navigational deflector, warp drive, fuel, and environmental support.I'd like to see evidence that this "cramming" is even possible.
If you don't believe me, click here and believe TrekCore.
Proof that they do is not required to speak of the maximum yield.Besides, do we even have proof that both tanks are filled with antimatter, and not just one?
I'm sure, in fact, that there are cases where you would just load one module, or a smaller module pair.