How much neutronium and anti-neutronium would be needed?

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Who is like God arbour
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How much neutronium and anti-neutronium would be needed?

Post by Who is like God arbour » Wed May 23, 2007 12:05 pm

  1. Assume, that there is neutronium, which can be taken out of a neutron star!
  2. Assume, that there is anti-neutronium to this neutronium!
How much (mass and volume) neutronium and anti-neutronium have to annihilate each other to release 1E38 joules energy?
Last edited by Who is like God arbour on Tue Jun 05, 2007 12:01 pm, edited 2 times in total.

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l33telboi
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Post by l33telboi » Wed May 23, 2007 1:06 pm

E=mc^2 would tell you how much mass you'd need, unless there's something funky about the mass Neutronium (except it being super-dense, of course).

How much volume that mass would take up i wouldn't know though.

Estrecca
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Post by Estrecca » Thu May 24, 2007 12:03 pm

1.1E21 kg or 1.1E18 tons. Roughly the mass of the asteroid Ceres.

Real life Neutronium has densities of 8E13 kg/m^3-2E15 kg/m^3, according to Wikipedia, suggesting that 13.8 million cubic meters at a minimum and 550.000 cubic meters at a maximum would be needed to store that much neutronium.

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Post by Nonamer » Fri May 25, 2007 12:19 am

Density is 4 * 10 ^ 17 kg/m^3 according to that site. So (1.1e21 kg) / (4e17 kg/m^3) = 2750 m^3. Cube rooting it gets you a cube ~14.01 m on a side.

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Who is like God arbour
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Post by Who is like God arbour » Tue Jun 05, 2007 12:04 pm

That's why I have asked this question.

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SailorSaturn13
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Post by SailorSaturn13 » Sun Jun 10, 2007 1:31 am

Nonamer wrote:Density is 4 * 10 ^ 17 kg/m^3 according to that site. So (1.1e21 kg) / (4e17 kg/m^3) = 2750 m^3. Cube rooting it gets you a cube ~14.01 m on a side.
The latter is correct, given that a neutron star has a diameter of 20-50 km and mass of 2-4*10^30 kg*(with heavier stars having SMALLER diameter!!).

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